document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=892105>Question 892105</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ok the question is they gave me a diagram of a right angle triangle ABC. X-7 is the adjacent,x is the opposite and x+1 is my hypotenuse.The question is show that x^2-16x+48=0.i tried Pythagoras theorem but failed.how to derive that ans x^2-16x+48=0.HELP TMR IS MY EXAM URGENT HELP PLEASE </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540280 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540280\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you use the pythagorean theorem.\r<BR>\n" );
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document.write( "that states that a^2 + b^2 = c^2\r<BR>\n" );
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document.write( "c is the hypotenuse.<BR>\n" );
document.write( "a is one of the legs<BR>\n" );
document.write( "b is the other of the legs.\r<BR>\n" );
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document.write( "since there's no angle involved, it doesn't matter which is the adjacent side or the opposite side.\r<BR>\n" );
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document.write( "that only comes into play when you are looking for a trig function related to that triangle.\r<BR>\n" );
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document.write( "in your problem, you can make:\r<BR>\n" );
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document.write( "a = x-7<BR>\n" );
document.write( "b = x<BR>\n" );
document.write( "c = x+1\r<BR>\n" );
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document.write( "the only restriction is that c had to be equal to x+1 because c is the hypotenuse of the right triangle.\r<BR>\n" );
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document.write( "a^2 + b^2 = c^2 becomes (x-7)^2 + x^2 = (x+1)^2\r<BR>\n" );
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document.write( "multiply these factors out and you get:\r<BR>\n" );
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document.write( "x^2 - 14x + 49 + x^2 = x^2 + 2x + 1\r<BR>\n" );
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document.write( "subtract (x^2 + 2x + 1) from both sides of the equation and you are left with:\r<BR>\n" );
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document.write( "x^2 - 14x + 49 + x^2 - (x^2 + 2x + 1) = 0\r<BR>\n" );
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document.write( "simplify this to get:\r<BR>\n" );
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document.write( "x^2 - 14x + 49 + x^2 - x^2 - 2x - 1 = 0\r<BR>\n" );
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document.write( "combine like terms to get:\r<BR>\n" );
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document.write( "x^2 - 16x + 48 = 0\r<BR>\n" );
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document.write( "i believe that's the equation you are looking for.\r<BR>\n" );
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document.write( "you had the right idea using the pythagorean theorem but you failed somewhere in the execution.\r<BR>\n" );
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