document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=892015>Question 892015</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two men startedtogether to walk a distance at 3 km per hour and 4 km per hour respectivelythe former arrives 30 mts before the latter find distance the walked<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540220 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> two men startedtogether to walk a distance at 3 km per hour and 4 km per hour respectivelythe former arrives 30 mts before the latter find distance the walked<BR>\n" );
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document.write( "Pitiful typing.<BR>\n" );
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document.write( "I'll assume 30 mts means 30 minutes = 0.5 hours<BR>\n" );
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document.write( "d = r*t<BR>\n" );
document.write( "r = slower rate<BR>\n" );
document.write( "3*(t+0.5) = 4t<BR>\n" );
document.write( "3t + 1.5 = 4t<BR>\n" );
document.write( "t = 1.5 hours<BR>\n" );
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document.write( "d = 4t = 6 km<BR>\n" );
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document.write( "PS  the \"respectively\" serves no purpose, tho that was probably in the question you copied. </SPAN>\n" );
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