document.write( "Question 891983: Gregory can mow the family's lawn in 3 hours, and Jennifer can mow it in 4 hours. If they team up to mow the lawn together, how long will it take to finish mowing the lawn? Hint: If they mow for x hours, Gregory will mow a fraction of the lawn that can be expressed as x/3. \n" ); document.write( "
Algebra.Com's Answer #540198 by ankor@dixie-net.com(22740)\"\" \"About 
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Gregory can mow the family's lawn in 3 hours, and Jennifer can mow it in 4 hours.
\n" ); document.write( " If they team up to mow the lawn together, how long will it take to finish mowing the lawn?
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\n" ); document.write( "let x = time required when mowing together (two lawn mowers, obviously)
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\n" ); document.write( "Let the completed job = 1 (a mowed lawn)
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\n" ); document.write( "Each will do a fraction of the lawn, the two fractions add up to
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\n" ); document.write( "\"x%2F3\" + \"x%2F4\" = 1
\n" ); document.write( "Multiply the equation thru by 12, cancel the denominators and you have:
\n" ); document.write( "4x + 3x = 12
\n" ); document.write( "7x = 12
\n" ); document.write( "x = 12/7
\n" ); document.write( "x = 1.71 hrs or 1 + .71(60) = 1 hr 43 min \n" ); document.write( "
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