document.write( "Question 891965: Sarah is twice the age Linda is. 6 years ago, Sarah was four times the age of Linda. What was their ages six years ago as well as their ages now?\r
\n" ); document.write( "\n" ); document.write( "Side note: M'techer sad it ain't 12, 3, 18, and 9. \n" ); document.write( "
Algebra.Com's Answer #540173 by LinnW(1048)\"\" \"About 
You can put this solution on YOUR website!
Set x = Sarah's current age
\n" ); document.write( "Set y = Linda's current age
\n" ); document.write( "Sarah's age 6 years ago was (x-6)
\n" ); document.write( "Linda's age 6 years ago was (y-6)
\n" ); document.write( "x = 2y
\n" ); document.write( "(x-6)=4(y-6)
\n" ); document.write( "Now substitute 2y for x in the equation above
\n" ); document.write( "((2y)-6)=4(y-6)
\n" ); document.write( "2y-6 = 4y - 24
\n" ); document.write( "add -4y to each side
\n" ); document.write( " -2y - 6 = -24
\n" ); document.write( "add 6 to each side
\n" ); document.write( " -2y = -18
\n" ); document.write( "divide each side by -2
\n" ); document.write( " y = 9
\n" ); document.write( "Since x = 2y, x = 18
\n" ); document.write( "Sarah is currently 18 and Linda is 9
\n" ); document.write( "Six years ago they were 12 and 3
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\n" ); document.write( "I am not sure what M'techer is thinking.
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