document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=891963>Question 891963</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular storage area is to be constructed along the side of a tall building. A security fence is required along the remaining 3 sides of the area. What is the maximum area that can be enclosed with 100 meters of fencing?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540172 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the two parallel sides have length of x meters each.  Then the third remaining side has length 100 - 2x meters.  The area would then be A(x) = x(100 - 2x).  The graph of this is a parabola facing downward, with x-intercepts at x = 0 and x = 50.  The highest point (vertex) would then be situated where x = 25, midway between the two x-intercepts (roots).  The largest area would then be 25* 50 = 1250 square meters. </SPAN>\n" );
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