document.write( "Question 891923: Hi, this is my first time asking a question :D\r
\n" ); document.write( "\n" ); document.write( "If \"+log%28+2%2C+12+%29+\" = a , find \"+log%28+2%2C+18+%29+\" in terms of a.\r
\n" ); document.write( "\n" ); document.write( "I tried to break down \"+log%28+2%2C+18+%29+\" to something like \"+log%28+2%2C+216%2F12+%29+\" . Then, \"+log%28+2%2C+216+%29+\" - \"+log%28+2%2C+12+%29+\" so that it can be simplified to \"+log%28+2%2C+216+%29+\" - a . But I couldn't do anything more. I tried other ways but this method seemed to be the best.\r
\n" ); document.write( "\n" ); document.write( "The answer says 2a - 3 but it does not provide any explanation. Could you guide me through this question?\r
\n" ); document.write( "\n" ); document.write( "I tried to work it out backwards using this answer 2a - 3. I got \"+log%28+2%2C+144+%29+\" - 3 . Then \"+log%28+2%2C+144+%29+\" - \"+log%28+2%2C+8+%29+\". And finally \"+log%28+2%2C+144%2F8+%29+\" which gives me \"+log%28+2%2C+18+%29+\". Supposing I did not know the answer, how can I work it out to get 2a - 3? Thank you in advance.
\n" ); document.write( "

Algebra.Com's Answer #540160 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Answer is \"2a-3\".
\n" ); document.write( "Tricky, but here is the trick.......\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"log%282%2C12%29=a\"
\n" ); document.write( "\"a=log%282%2C2%2A2%2A3%29\"
\n" ); document.write( "\"log%282%2C%28%282%5E2%29%2A3%29%29\"
\n" ); document.write( "\"log%282%2C2%5E2%29%2Blog%282%2C3%29\"
\n" ); document.write( "\"2%2Alog%282%2C2%29%2Blog%282%2C3%29\"
\n" ); document.write( "\"2%2Blog%282%2C3%29=a\"
\n" ); document.write( "\"highlight_green%28log%282%2C3%29=a-2%29\"---This is what you will use.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now Starting at \"log%282%2C18%29\",
\n" ); document.write( "\"log%282%2C%282%2A3%5E2%29%29\"
\n" ); document.write( "\"log%282%2C2%29%2Blog%282%2C%283%5E2%29%29\"
\n" ); document.write( "\"1%2B2%2Alog%282%2C3%29\"-----You simply substitute what you just found for \"log%282%2C3%29\" !
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "
\n" ); document.write( "
\n" );