document.write( "Question 891914: A boat can travel 36 miles downstream in 2 hours. Coming back upstream,, the boat takes 3 hours. What is the rate of the boat in still water? What is the rate of the current? \n" ); document.write( "
Algebra.Com's Answer #540148 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+c+\" = the rate of the current in mi/hr
\n" ); document.write( "Let \"+s+\" = the speed of the boat in still water
\n" ); document.write( "----------------
\n" ); document.write( "Going downstream:
\n" ); document.write( "(1) \"+36+=+%28+s+%2B+c+%29%2A2+\"
\n" ); document.write( "Going upstream:
\n" ); document.write( "(2) \"+36+=+%28+s+-+c+%29%2A3+\"
\n" ); document.write( "---------------------
\n" ); document.write( "(1) \"+2s+%2B+2c+=+36+\"
\n" ); document.write( "(2) \"+3s+-+3c+=+36+\"
\n" ); document.write( "--------------------
\n" ); document.write( "(1) \"+s+%2B+c+=+18+\"
\n" ); document.write( "(2) \"+s+-+c+=+12+\"
\n" ); document.write( "Add the equations
\n" ); document.write( "\"+2s+=+30+\"
\n" ); document.write( "\"+s+=+15+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+15+%2B+c+=+18+\"
\n" ); document.write( "(1) \"+c+=+3+\"
\n" ); document.write( "The rate of the boat in still water is 15 mi/hr
\n" ); document.write( "The speed of the current is 3 mi/hr
\n" ); document.write( "------------------
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+36+=+%28+s+%2B+c+%29%2A2+\"
\n" ); document.write( "(1) \"+36+=+%28+15+%2B+3+%29%2A2+\"
\n" ); document.write( "(1) \"+36+=+18%2A2+\"
\n" ); document.write( "(1) \"+36+=+36+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+36+=+%28+s+-+c+%29%2A3+\"
\n" ); document.write( "(2) \"+36+=+%28+15+-+3+%29%2A3+\"
\n" ); document.write( "(2) \"+36+=+12%2A3+\"
\n" ); document.write( "(2) \"+36+=+36+\"
\n" ); document.write( "OK\r
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