document.write( "Question 891879: a man was 4 times less than 1 year as old as his son 5years ago.in 4 years time,the man wil b 2time plus4 years as old the son.find their present age \n" ); document.write( "
Algebra.Com's Answer #540138 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let m = man's present age \n" ); document.write( "let s = son's present age \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement; simplify as much as possible \n" ); document.write( ": \n" ); document.write( "a man was 4 times less than 1 year as old as his son 5years ago. \n" ); document.write( "m - 5 = 4(s-5) - 1 \n" ); document.write( "m - 5 = 4s - 20 - 1 \n" ); document.write( "m = 4s - 20 - 1 + 5 \n" ); document.write( "m = 4s - 16 \n" ); document.write( ": \n" ); document.write( "in 4 years time, the man wil b 2time plus4 years as old the son. \n" ); document.write( "m + 4 = 2(s+4) + 4 \n" ); document.write( "m + 4 = 2s + 8 + 4 \n" ); document.write( "m + 4 = 2s + 12 \n" ); document.write( "m = 2s + 12 - 4 \n" ); document.write( "m = 2s + 8 \n" ); document.write( ": \n" ); document.write( "m = m, therefore we can write the two equations as \n" ); document.write( "4s - 16 = 2s + 8 \n" ); document.write( "4s - 2s = 8 + 16 \n" ); document.write( "2s = 24 \n" ); document.write( "s = 12 yrs is the son \n" ); document.write( ": \n" ); document.write( "I'll you find the man's age using the 1st equation, check the solutions in the 2nd equation\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "find their present age \n" ); document.write( " |