document.write( "Question 891878: How much should be deposited in an account paying 4.75% interest, compounded semi-annually, in order to have a balance of $7,000 after 5 years and 6
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document.write( "months?
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document.write( "Enter the answer in dollars and cents, and round to the nearest cent, if needed. Do not include the dollar sign. For example, if the answer is $0.61, only the
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document.write( "number 0.61 should be entered.
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document.write( "Principal $ ____________ \n" );
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Algebra.Com's Answer #540113 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! We'll use the formula A = P*(1+r/n)^(n*t) where...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = 7000 \n" ); document.write( "P = unknown \n" ); document.write( "r = 4.75% = 0.0475 \n" ); document.write( "n = 2 (compounding 2 times per year) \n" ); document.write( "t = 5 yrs, 6 months = 5.5 years\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug those values in and solve for P to get\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " A = P*(1+r/n)^(n*t)\r\n" ); document.write( "\r\n" ); document.write( " 7000 = P*(1+0.0475/2)^(2*5.5)\r\n" ); document.write( "\r\n" ); document.write( " 7000 = P*(1+0.02375)^(11)\r\n" ); document.write( "\r\n" ); document.write( " 7000 = P*(1.02375)^(11)\r\n" ); document.write( "\r\n" ); document.write( " 7000 = P*1.29459242778672\r\n" ); document.write( "\r\n" ); document.write( " 7000/1.29459242778672 = P\r\n" ); document.write( "\r\n" ); document.write( " 5407.1071711484 = P\r\n" ); document.write( "\r\n" ); document.write( " P = 5407.1071711484\r\n" ); document.write( "\r\n" ); document.write( " P = 5407.11\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You need to deposit $5,407.11 \n" ); document.write( " |