document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=891864>Question 891864</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 5m longer than the width. What are the dimensions if the area is 36m^2? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540095 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L * W = Area<BR>\n" );
document.write( "You're given both the length and the area. L=W+5<BR>\n" );
document.write( "36 m^2 = (W+5) * W<BR>\n" );
document.write( "Easiest way to solve this is to find the factors of 36<BR>\n" );
document.write( "36,1<BR>\n" );
document.write( "18,2<BR>\n" );
document.write( "9,4<BR>\n" );
document.write( "6,6<BR>\n" );
document.write( "Which of those pairs fits the equation L = W+5?  L is the first factor, W is the second. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );