document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=891769>Question 891769</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which angle corresponds to the point (1, 0) on the Unit Circle?\r<BR>\n" );
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document.write( "&#960; <BR>\n" );
document.write( "2&#960; <BR>\n" );
document.write( "&#960; /2<BR>\n" );
document.write( "non of these<BR>\n" );
document.write( "3&#960; /2\r<BR>\n" );
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document.write( "help me please <BR>\n" );
document.write( "thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540078 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540078\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28300%2C300%2C-1.2%2C1.2%2C-1.2%2C1.2%2C%0D%0Agrid%280%29%2Cred%28circle%280%2C0%2C1%29%29%2Ccircle%281%2C0%2C0.01%29%2C%0D%0Aarrow%281.15%2C0.5%2C1.015%2C0.05%29%2Clocate%280.9%2C0.65%2CP%281%2C0%29%29%2C%0D%0Agreen%28arc%280%2C0%2C1.6%2C1.6%2C270%2C360%29%29%2Cgreen%28arc%280%2C0%2C1.6%2C1.6%2C180%2C270%29%29%2C%0D%0Agreen%28arc%280%2C0%2C1.6%2C1.6%2C90%2C180%29%29%2Cgreen%28arc%280%2C0%2C2%2C1.6%2C0%2C90%29%29%2C%0D%0Agreen%28line%280.9%2C-0.1%2C1%2C0%29%29%2Cgreen%28line%281.1%2C-0.1%2C1%2C0%29%29%2C%0D%0Alocate%28-0.56%2C-0.46%2Cgreen%282pi%29%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > The angle is measured counterclockwise from the positive x-axis.<BR>\n" );
document.write( "As the point (1,0) is on the positive x-axis, we could say that the angle is zero, but it could also be a whole counterclockwise turn around the circle.<BR>\n" );
document.write( "Since the whole circumference measures <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi ALIGN=MIDDLE  ALT=\"2pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > ,<BR>\n" );
document.write( "a whole counterclockwise turn is an angle of  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%282pi%29 ALIGN=MIDDLE  ALT=\"highlight%282pi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > radians.<BR>\n" );
document.write( "Maybe there is some convention, accepted by many, that says angles corresponding to a point are to be expressed as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=theta ALIGN=MIDDLE  ALT=\"theta\"   DISABLED_style= \"max-width:90%; height:auto;\" > with <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0%3Ctheta%3C=2pi ALIGN=MIDDLE  ALT=\"0%3Ctheta%3C=2pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > .<BR>\n" );
document.write( "If so, I do not know about it.<BR>\n" );
document.write( "We could also say that the angle is 2 counterclockwise turns, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4pi ALIGN=MIDDLE  ALT=\"4pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > , or any number of clockwise  or counterclockwise turns, like <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1002pi ALIGN=MIDDLE  ALT=\"1002pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-12pi ALIGN=MIDDLE  ALT=\"-12pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > .<BR>\n" );
document.write( "None of those is a given choice.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi ALIGN=MIDDLE  ALT=\"pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > is an half turn and correspond to point (-1,0) at the left end of the circle.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2F2=%281%2F4%29%2A2pi ALIGN=MIDDLE  ALT=\"pi%2F2=%281%2F4%29%2A2pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F4 ALIGN=MIDDLE  ALT=\"1%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > of a counterclockwise turn, and corresponds to point (0,1) at the top of the circle.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3pi%2F2=%283%2F4%29%2A2pi ALIGN=MIDDLE  ALT=\"3pi%2F2=%283%2F4%29%2A2pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F4 ALIGN=MIDDLE  ALT=\"3%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > of a counterclockwise turn, and corresponds to point (0,-1) at the bottom of the circle. </SPAN>\n" );
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