document.write( "Question 75181: Find digits a and b such that the number 34a47b5893 is divisible by 99. \n" ); document.write( "
Algebra.Com's Answer #54005 by nilan(17) ![]() You can put this solution on YOUR website! Suppose 34a47b5893 is divisible by 99 \n" ); document.write( "Then obviously it is divisible by 9 \n" ); document.write( "If a number is divisible by 9 the sum of all the digits should divisible by 9 (this can be easily proved)\r \n" ); document.write( "\n" ); document.write( "For example let the number abcd divisible by 9 then \n" ); document.write( " \n" ); document.write( "Then \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "then a+b+d+c is divisible by 9 \n" ); document.write( "This can be proved for any number (can be given a general proof. Try it)\r \n" ); document.write( "\n" ); document.write( "Again to the problem \n" ); document.write( "Then the sum of 34a47b5893 is divisible by 9\r \n" ); document.write( "\n" ); document.write( "Then 3+4+a+4+7+b+5+8+9+3 is divisible by 9 \n" ); document.write( "Then \n" ); document.write( "43+a+b is divisible by nine \r \n" ); document.write( "\n" ); document.write( "Then a=0 and b=2 \n" ); document.write( "Or a=2 and b = 0 \n" ); document.write( " |