document.write( "Question 891790: if (xyz)^0 is equal to 1
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Algebra.Com's Answer #540036 by Edwin McCravy(20059) $\"\"$ $\"About$

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document.write( "It's equal to 1.\r\n" );
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document.write( "But the converse is not true.\r\n" );
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document.write( " is meaningless.\r\n" );
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document.write( "Since you are given that (xyz)^0 = 1 then you are certain that \r\n" );
document.write( "none of x,y, and z are 0, because if one of them were, then \r\n" );
document.write( "(xyz)^0 would be meaningless, not 1.\r\n" );
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document.write( "-----\r\n" );
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document.write( "But suppose it had been this way instead:\r\n" );
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document.write( "if (x+y+z)^0 is equal to 1\r\n" );
document.write( "then what is (xyz)^0 ?\r\n" );
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document.write( "Then if x and y were 1 and z were 0 then  would be  and\r\n" );
document.write( "that would be 1.  But then  would be meaningless, not 1, for it would be\r\n" );
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document.write( "Edwin

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