document.write( "Question 891700: log8-logx-log(x-2)=-1 \n" ); document.write( "
Algebra.Com's Answer #539982 by LinnW(1048)\"\" \"About 
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log8-logx-log(x-2)=-1
\n" ); document.write( "add -log8 to each side
\n" ); document.write( " -logx - log(x-2) = -1 -log8
\n" ); document.write( "multiply each side by -1
\n" ); document.write( " logx + log(x-2) = 1 + log8
\n" ); document.write( "Assuming log means log base 10
\n" ); document.write( " log(x) + log(x-2) = log(10) + log(8)
\n" ); document.write( "log(x(x-2)) = log(10*8)
\n" ); document.write( "log(x(x-2)) = log(80)
\n" ); document.write( " x(x-2) = 80
\n" ); document.write( " x^2 -2x = 80
\n" ); document.write( " x^2 -2x -80 = 0
\n" ); document.write( " (x-10)(x+8) = 0
\n" ); document.write( "so x = 10
\n" ); document.write( " \n" ); document.write( "
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