document.write( "Question 891711: A mother is 21 years older than her son. 6 years
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document.write( "from now exactly, the mother will be exactly 5 times
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document.write( "as old as the child. Where's the child's dad? \n" );
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Algebra.Com's Answer #539980 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! A mother is 21 years older than her son. \n" ); document.write( " \r\n" ); document.write( "Let the son be S years old\r\n" ); document.write( "Then the mother is S+21\r\n" ); document.write( " \n" ); document.write( "6 years from now exactly, the mother will be exactly 5 times \n" ); document.write( "as old as the child. \n" ); document.write( " \r\n" ); document.write( "S+21+6 = 5(S+6)\r\n" ); document.write( " S+27 = 5S+30\r\n" ); document.write( " -3 = 4S\r\n" ); document.write( " -3/4 = S \r\n" ); document.write( "\r\n" ); document.write( "So the son is negative three-fourths of a year old, which means\r\n" ); document.write( "he has not been born yet. Since three fourths of a year\r\n" ); document.write( "before he is born is 9 months before he is born, he is just\r\n" ); document.write( "being conceived.\r\n" ); document.write( " \n" ); document.write( "Where's the child's dad? \n" ); document.write( " \n" ); document.write( " |