document.write( "Question 891656: 2 men and 4 boys can do a piece of work in 10 days,
\n" );
document.write( "while 4 men and 5 boys can do it in 6 days. Men and
\n" );
document.write( "boys are paid wages according to their output. If the
\n" );
document.write( "daily wage of a man is `40, then the ratio of daily wages
\n" );
document.write( "of a man and a boy will be. \n" );
document.write( "
Algebra.Com's Answer #539965 by LinnW(1048)![]() ![]() You can put this solution on YOUR website! set b = boys rate in work projects per day \n" ); document.write( " m = mens rate in work projects per day \n" ); document.write( "10(2m + 4b) = 1 \n" ); document.write( "6(4m + 5b) = 1 \n" ); document.write( "Expanding the above \n" ); document.write( "20m + 40b = 1 \n" ); document.write( "24m + 30b = 1 \n" ); document.write( "Since each equation equals 1 \n" ); document.write( "20m + 40b = 24m + 30b \n" ); document.write( "add -20m to each side \n" ); document.write( " 40b = 24m -20m +30b \n" ); document.write( " 40b = 4m + 30b \n" ); document.write( "add -30b to each side \n" ); document.write( " 10b = 4m \n" ); document.write( "divide each side by 4 \n" ); document.write( " (10/4)b = m \n" ); document.write( " (2.5)b = m\r \n" ); document.write( "\n" ); document.write( "A mans output is 2.5 times a boys output\r \n" ); document.write( "\n" ); document.write( "Try entering the below into www.wolframalpha.com \n" ); document.write( "10(2m + 4b) = 1 ; 6(4m + 5b) = 1 \n" ); document.write( "The rate b = 1/90 and the rate m = 1/36 in terms of work projects per day. \n" ); document.write( " |