document.write( "Question 75154: Please help...Thanks!!
\n" ); document.write( "If a line contains the points (1,3), (2,6) and (3,9) determine and write the slope-intercept form of the equation, provide one additional point on this line in (x,y) form, and graph the function. \r
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Algebra.Com's Answer #53996 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
FIRST WE FIND THE SLOPE (Y2-Y1)/(X2-X1)
\n" ); document.write( "(6-3)/(2-1)
\n" ); document.write( "3/3=3 IS THE SLOPE.
\n" ); document.write( "NOW USING THE LINE FORMULA AND ONE SET OF POINTS WE CAN FIND THE Y INTERCEPT.
\n" ); document.write( "3=3*1+b
\n" ); document.write( "3=3+b
\n" ); document.write( "b=3-3
\n" ); document.write( "b=0 THUS THE EQUATION IS
\n" ); document.write( "Y=3X
\n" ); document.write( "SETTING Y=12 WE SOLVE FOR X
\n" ); document.write( "12=3*X
\n" ); document.write( "3X=12
\n" ); document.write( "X=12/3
\n" ); document.write( "X=4 OR (4,12) FOR THE ADDITIONAL POINT ON THIS LINE
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+3x%29+\" (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = 3x).
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