document.write( "Question 891589: Divide 56 into two parts such that 3/8 of the greater exceeds 1/4 of the smaller by 6.
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Algebra.Com's Answer #539957 by LinnW(1048)\"\" \"About 
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let x = the smaller part
\n" ); document.write( "This means 56-x is the smaller
\n" ); document.write( "(3/8)(56-x) - (1/4)(x) = 6
\n" ); document.write( "multiply each side by 8 to get rid of the fractions
\n" ); document.write( " 3(56-x) - 2(x) = 48
\n" ); document.write( " 168 - 3x - 2x = 48
\n" ); document.write( " 168 - 5x = 48
\n" ); document.write( "add -168 to each side
\n" ); document.write( " -5x = 48 -168
\n" ); document.write( " -5x = -120
\n" ); document.write( "divide each side by -5
\n" ); document.write( " x = 24
\n" ); document.write( "(56 -x ) = 56 - 24 = 32
\n" ); document.write( "So the larger is 32 and the smaller is 24
\n" ); document.write( "Plugging into our equation,
\n" ); document.write( "(3/8)(56-24) -(1/4)(24) ?= 6
\n" ); document.write( "(3/8)(32) - 6 ?= 6
\n" ); document.write( " 12 - 6 ?= 6 , clearly yes
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