document.write( "Question 891682: Hello. Hoping you can help me answer this question. A) write geometric series -9/2+3/2-1/2+1/6...+1/39366 in summation notation. B)using the formula for the sum of an geometric series, compute the sum. \r
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document.write( "Here's what I know. The numerator is multiplied by 1/3 to get from each term to the next. The denominator decreases by 1 when comparing n=term #, n=1 to denom in -9/2, 2-1=1, n=2 in 3/2, 2-2=0 and so on. I see the pattern, just not sure how to write it. Also, when writing it in sn, I know my bottom starting amount will be n=1\r
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document.write( "Any help you can give would be appreciated. Thank you. \n" );
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Algebra.Com's Answer #539950 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! It looks like each successive number is multiplied by \n" ); document.write( "2nd term : \n" ); document.write( "3rd term : \n" ); document.write( "4th term : \n" ); document.write( "So then, continuing on, \n" ); document.write( " \n" ); document.write( "The constant term would be, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So then, the series would look like, \n" ); document.write( " \n" ); document.write( "The sum would then be, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So for \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |