document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=10210>Question 10210</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Here is the question:\r<BR>\n" );
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document.write( "If the length of a rectangular field is 8 feet more than double its width. Find the dimensions of the filed if its area is 540 square feet?\r<BR>\n" );
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document.write( "I know you have to use A = l * w, but how do you start. I started like this:\r<BR>\n" );
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document.write( "540 = (8 + x) ( x^2)\r<BR>\n" );
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document.write( "would it then be :  540 = 8x + x^2? \r<BR>\n" );
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document.write( "Then do you have to subtract 540 from the left side to bring it to the right?\r<BR>\n" );
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document.write( " 8x + x^2 - 540 = 0\r<BR>\n" );
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document.write( "I'm lost. Please help. I appreciate all your help. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5399 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5399\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, you've got the right idea!\r<BR>\n" );
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document.write( "A = L*W but L = 2W+8 Because the length (L) is 8 ft more (+8) than twice the width (2W).\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282W%2B8%29%28W%29+=+540 ALIGN=MIDDLE  ALT=\"%282W%2B8%29%28W%29+=+540\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2W%5E2+%2B+8W+=+540 ALIGN=MIDDLE  ALT=\"2W%5E2+%2B+8W+=+540\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 540 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2W%5E2+%2B+8W+-+540+=+0 ALIGN=MIDDLE  ALT=\"2W%5E2+%2B+8W+-+540+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Solve this quadratic for W. Factor a 2 to simplify it a bit.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w%5E2+%2B+4W+-+270+=+0 ALIGN=MIDDLE  ALT=\"w%5E2+%2B+4W+-+270+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >  Since this doesn't factor you can solve it by using the quadratic formula:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a ALIGN=MIDDLE  ALT=\"W=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Here, a = 1, b = 4, and c = -270.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+%28-4%2B-sqrt%284%5E2-4%2A1%2A%28-270%29%29%29%2F%282%2A1%29 ALIGN=MIDDLE  ALT=\"W+=+%28-4%2B-sqrt%284%5E2-4%2A1%2A%28-270%29%29%29%2F%282%2A1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+%28-4%2B-sqrt%2816%2B1080%29%29%2F2 ALIGN=MIDDLE  ALT=\"W+=+%28-4%2B-sqrt%2816%2B1080%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+%28-4%2B-sqrt%281096%29%29%2F2 ALIGN=MIDDLE  ALT=\"W+=+%28-4%2B-sqrt%281096%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+-2%2B%281%2F2%29%2833.106%29 ALIGN=MIDDLE  ALT=\"W+=+-2%2B%281%2F2%29%2833.106%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+-2-%281%2F2%29%2833.106%29 ALIGN=MIDDLE  ALT=\"W+=+-2-%281%2F2%29%2833.106%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+-2%2B16.55 ALIGN=MIDDLE  ALT=\"W+=+-2%2B16.55\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+-2-16.55 ALIGN=MIDDLE  ALT=\"W+=+-2-16.55\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+14.55 ALIGN=MIDDLE  ALT=\"W+=+14.55\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+-18.55 ALIGN=MIDDLE  ALT=\"W+=+-18.55\"   DISABLED_style= \"max-width:90%; height:auto;\" > Discard the 2nd solution as width can only be positive. Note: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%281096%29+=+33.1058907145 ALIGN=MIDDLE  ALT=\"sqrt%281096%29+=+33.1058907145\"   DISABLED_style= \"max-width:90%; height:auto;\" > approx, so I rounded it to 33.106 Finally:<BR>\n" );
document.write( " The length = 2W+8 = 2(14.55)+8 = 29.1+8 = 37.1 ft.<BR>\n" );
document.write( "The width = 14.55 ft.\r<BR>\n" );
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document.write( "Check:\r<BR>\n" );
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document.write( "A = L*W = (37.1)(14.55) = 539.805 sq.ft. which is pretty darn close to 540 sq.ft. \r<BR>\n" );
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document.write( " </SPAN>\n" );
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