document.write( "Question 891639: if te area of the circle is 72sq,m,then what percentage of area of circle is coverd by sector
\n" ); document.write( "given angle in sector is 135'
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Algebra.Com's Answer #539892 by lwsshak3(11628)\"\" \"About 
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if te area of the circle is 72sq,m,then what percentage of area of circle is coverd by sector
\n" ); document.write( "given angle in sector is 135'
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\n" ); document.write( "area of circle=πr^2=72
\n" ); document.write( "r^2=72/π
\n" ); document.write( "area of sector=1/2r^2theta, r=radius, theta in radians
\n" ); document.write( "135˚=135π/180 radians
\n" ); document.write( "area of sector=1/2*72/π*135π/180=36*135/180
\n" ); document.write( "area of sector/area of circle=(36*135/180)/72=.375=37.5%
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