document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=886166>Question 886166</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if sinA +cosB =2. find sin(2A+B/3) ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #539891 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=539891\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> max[sin(x)]=max[cos(x)]=1<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "A=pi/2 plus/minus 2pi<BR>\n" );
document.write( "B=0 plus/minus 2pi\r<BR>\n" );
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document.write( "and so\r<BR>\n" );
document.write( "\n" );
document.write( "2A+B/3=pi\r<BR>\n" );
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document.write( "and this means\r<BR>\n" );
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document.write( "sin(2A+B/3)=0<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );