document.write( "Question 891573: Can you please help me solve this question? Many of the terms have a # or a letter with a # or letter written just below it. I will use \"sub\" showing what is written that is lowered. It's like the opposite location from an exponent. \r
\n" ); document.write( "\n" ); document.write( "List the first six terms of the sequence defined recursively by (1) z(sub 1)=0, z(sub 2)=1, z (sub 3)=2, and (2) for m>=4, z(sub m)=z (sub m-1) + 2z(sub m-2) + 3z (sub m-3).\r
\n" ); document.write( "\n" ); document.write( "I sure hope that doesn't sound confusing. Any help you can give would be much appreciated. Thank you.
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Algebra.Com's Answer #539883 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
You are given the first 3 terms as \"system%28z%5B1%5D=0%2Cz%5B2%5D=1%2Cz%5B3%5D=2%29\"
\n" ); document.write( "and for the other terms you are given a recursive formula to calculate a term from the 3 previous terms:
\n" ); document.write( "for \"m%3E=4\" , \"z%5Bm%5D=z%5B%28m-1%29%5D+%2B+2z%5B%28m-2%29%5D%2B+3z%5B%28m-3%29%5D\" .
\n" ); document.write( "Using that formula:
\n" ); document.write( " ,
\n" ); document.write( " , and
\n" ); document.write( " .
\n" ); document.write( "So the first 6 terms are: 0, 1, 2, 4, 11, 25 .
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