document.write( "Question 891537: Please help me on this problem, thanks!
\n" ); document.write( "The perimeter of the rectangle below is 78 feet. Find it's Dimension. One of the side on the rectangle is 2x-4 and the other side is 2x+3 and the other two are blank
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Algebra.Com's Answer #539805 by Theo(13342)\"\" \"About 
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P = perimeter
\n" ); document.write( "L = length
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\n" ); document.write( "\n" ); document.write( "P = 2L + 2W\r
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\n" ); document.write( "\n" ); document.write( "P = 78\r
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\n" ); document.write( "\n" ); document.write( "L = 2x-4
\n" ); document.write( "W = 2x+3\r
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\n" ); document.write( "\n" ); document.write( "P = 2L + 2W becomes:\r
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\n" ); document.write( "\n" ); document.write( "78 = 2(2x-4) + 2(2x+3)\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "78 = 4x - 8 + 4x + 6\r
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\n" ); document.write( "\n" ); document.write( "simplify to get 78 = 8x - 2\r
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\n" ); document.write( "\n" ); document.write( "add 2 to both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "80 = 8x\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of the equation by 8 to get:\r
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\n" ); document.write( "\n" ); document.write( "x = 10\r
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\n" ); document.write( "\n" ); document.write( "when x = 10, your original equation of:\r
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\n" ); document.write( "\n" ); document.write( "78 = 2(2x-4) + 2(2x+3) becomes:\r
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\n" ); document.write( "\n" ); document.write( "78 = 2(2*10-4) + 2(2*10+3) which becomes:\r
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\n" ); document.write( "\n" ); document.write( "78 = 2 * 16 + 2 * 23 which becomes:\r
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\n" ); document.write( "\n" ); document.write( "78 = 32 + 46 which becomes:\r
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\n" ); document.write( "\n" ); document.write( "78 = 78\r
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\n" ); document.write( "\n" ); document.write( "this confirms the solution os x = 10 is correct.\r
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