document.write( "Question 75192: The equationh=-16t^2+112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180 ft. \r
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document.write( "please show your work \n" );
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Algebra.Com's Answer #53979 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! h(t)=-16t^2+112t \n" ); document.write( "Let the height be 180 ft. then: \n" ); document.write( "-16t^2+112t-180=0 \n" ); document.write( "4(-4t^2+28t-45)=0 \n" ); document.write( "Use the Quadratic Formula to find \"t\". \n" ); document.write( "t=[-28+-sqrt(784-4*-4*-45)]/-8 \n" ); document.write( "t=[-28+-8]/-8 \n" ); document.write( "t=-36/-8=4.5 seconds \n" ); document.write( "=========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |