document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=75189>Question 75189</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ruth invest $10,000 dollarsin two accounts. one account has an annual interest rate of 7%, and the other account has an annual interest rate of 5%. Let I represent the total interest earned in one year. Then Ruth's investemnt can be modeled by the system of equations x+y=10,000 and 0.07x=0.05y=I.\r<BR>\n" );
document.write( "\n" );
document.write( "   a. determind a solution fo this system of equations that represents a possible investment, and find the value of I that corresponds to your solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53976 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53976\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ruth invest $10,000 dollarsin two accounts. one account has an annual interest rate of 7%, and the other account has an annual interest rate of 5%. Let I represent the total interest earned in one year. Then Ruth's investemnt can be modeled by the system of equations x+y=10,000 and 0.07x+0.05y=I.<BR>\n" );
document.write( "-----------------------------------<BR>\n" );
document.write( "a. determin a solution fo this system of equations that represents a possible investment, and find the value of I that corresponds to your solution.<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "Let amount invested at 7% be \"x\"  ; Interest is 0.07x dollars<BR>\n" );
document.write( "Let amount invested at 5% by \"y\"  ; Interest is 0.05y dollars<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "equations x+y=10,000 and 0.07x+0.05y=I<BR>\n" );
document.write( "x=10000-y<BR>\n" );
document.write( "0.07(1000-y)+0.05y =I<BR>\n" );
document.write( "7000-0.02y=I<BR>\n" );
document.write( "y=(7000-I)/0.02<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "Substitute any number you want for \"I\" and you can solve for \"y\" and then \"x\".<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );