document.write( "Question 891420: √x+√(x+7)=7
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Algebra.Com's Answer #539728 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
You want to square this on both sides, TWICE. Some adjustments between the first and second squaring is needed.\r
\n" ); document.write( "\n" ); document.write( "First Squaring
\n" ); document.write( "\"sqrt%28x%29%2Bsqrt%28x%2B7%29=7\"
\n" ); document.write( "\"x%2B2sqrt%28x%29sqrt%28x%2B7%29%2Bx%2B7=49\"
\n" ); document.write( "\"2sqrt%28x%29sqrt%28x%2B7%29=49-2x-7\"
\n" ); document.write( "\"2sqrt%28x%29sqrt%28x%2B7%29=42-2x\"
\n" ); document.write( "\"sqrt%28x%29sqrt%28x%2B7%29=21-x\"
\n" ); document.write( "Second Squaring
\n" ); document.write( "\"x%2A%28x%2B7%29=%2821-x%29%5E2\"
\n" ); document.write( "\"x%5E2%2B7x=441-42x%2Bx%5E2\"
\n" ); document.write( "\"7x=441-42x\"
\n" ); document.write( "\"7x%2B42x=441\"
\n" ); document.write( "\"49x=441\"
\n" ); document.write( "\"x=441%2F49\"
\n" ); document.write( "\"x=%2821%2A21%29%2F%287%2A7%29\"
\n" ); document.write( "\"highlight%28x=9%29\"
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