document.write( "Question 891417: The width of a rectangle is two inches longer than one-third of its length. Find the width and the length if the perimeter is 68 inches. \n" ); document.write( "
Algebra.Com's Answer #539723 by JulietG(1812)\"\" \"About 
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Perimeter = 2L + 2W
\n" ); document.write( "W = \"1%2F3\"L + 2
\n" ); document.write( "Substitute the value of W from the second equation into the first
\n" ); document.write( "P = 2L + 2W
\n" ); document.write( "68 = 2L + 2(\"1%2F3\"L+2)
\n" ); document.write( "68 = 2L + \"2%2F3\"L + 4
\n" ); document.write( "Subtract 4 from each side
\n" ); document.write( "64 = 2\"2%2F3\"L
\n" ); document.write( "64 = \"8%2F3\"L
\n" ); document.write( "Multiply each side by \"3%2F8\"
\n" ); document.write( "24 = L
\n" ); document.write( "If the length is 24, the width is \"1%2F3\" of that + 2, or 10
\n" ); document.write( "24 + 24 + 10 + 10 = 68
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