document.write( "Question 75152: I don't really understand this.. well i kind of do but i kind of don't:\r
\n" ); document.write( "\n" ); document.write( "3x+2y=12
\n" ); document.write( "2x+5y=8\r
\n" ); document.write( "\n" ); document.write( "I don't know how to do it because there is no \"y=\" or \"x=\" and it get confused on these. would you take (3x+2y=12) and multiply that by negative 2... and then take (2x+5y=8) and multiply that by positive 3?.... i don't know.. but if thats correct, I don't know what to do next.
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Algebra.Com's Answer #53970 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve the system of equations:
\n" ); document.write( "1) \"3x%2B2y+=+12\"
\n" ); document.write( "2) \"2x%2B5y+=+8\"
\n" ); document.write( "Your suggestion is a good one.
\n" ); document.write( "1a) \"-2%283x%2B2y%29+=+-2%2812%29\"
\n" ); document.write( "1a) \"-6x-4y+=+-24\"
\n" ); document.write( "2a) \"3%282x%2B5y%29+=+3%288%29\"
\n" ); document.write( "2a) \"6x%2B15y+=+24\"
\n" ); document.write( "Now add equations 1a) and 2a)
\n" ); document.write( "1a) \"-6x-4y+=+-24\"
\n" ); document.write( "2a) \"6x%2B15y+=+24\"
\n" ); document.write( "------------------------
\n" ); document.write( "3) \"11y+=+0\" so y = 0 Now substitute this value for y into either of the two original equations and solve for x.
\n" ); document.write( "1) \"3x%2B2y+=+12\" Set y = 0
\n" ); document.write( "\"3x%2B2%280%29+=+12\"
\n" ); document.write( "\"3x+=+12\" Divide both sides by 3.
\n" ); document.write( "\"x+=+4\"
\n" ); document.write( "The solution is: (4, 0)
\n" ); document.write( "Here's the graph showing the intersection (solution).
\n" ); document.write( "\"graph%28300%2C200%2C-5%2C7%2C-5%2C5%2C-%283%2F2%29x%2B6%2C-%282%2F5%29x%2B8%2F5%29\"
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