document.write( "Question 891388: how do i find the remaining zeros of the function\r
\n" ); document.write( "\n" ); document.write( "h(x)=2x^4+3x^3+96x^2+147x-98; zero: -7i \n" ); document.write( "

Algebra.Com's Answer #539696 by josgarithmetic(39621) $\"\"$ $\"About$

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\"How....?\"\r
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\n" ); document.write( "\n" ); document.write( "Try this:\r
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\n" ); document.write( "\n" ); document.write( "imaginary zeros occur in conjugate pair, so this means 7i is also a zero. This means there is a product $\"%28x-%28-7i%29%29%28x-7i%29\"$ , which becomes a quadratic factor with real integer coefficients.
\n" ); document.write( " $\"%28x%2B7i%29%28x-7i%29\"$
\n" ); document.write( " $\"x%5E2-%287i%29%5E2\"$
\n" ); document.write( " $\"x%5E2-49%2Ai%5E2\"$
\n" ); document.write( " $\"highlight_green%28x%5E2%2B49%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "Divide h(x) by $\"x%5E2%2B49\"$ using POLYNOMIAL DIVISION, unless you know another method, and then the quotient will be simpler to further reduce or factorize. (Meaning, finding the other two roots). \n" ); document.write( "

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