document.write( "Question 891327: I have 10 liters of a 40% water and 60% ethanol mixture. How much of an unlimited supply of 90% water and 10% ethanol mixture should i add to this mixture in order to dilute it to a concentration of 25% ethanol? \n" ); document.write( "

Algebra.Com's Answer #539680 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = liters of 10% ethanol mixture to be added
\n" ); document.write( " $\"+.6%2A10+=+6+\"$ liters of ethanol in 60% mixture
\n" ); document.write( " $\"+%28+6+%2B+.1x+%29+%2F+%28+10+%2B+x+%29+=+.25+\"$
\n" ); document.write( " $\"+6+%2B+.1x+=+.25%2A%28+10+%2B+x+%29+\"$
\n" ); document.write( " $\"+6+%2B+.1x+=+2.5+%2B+.25x+\"$
\n" ); document.write( " $\"+.15x+=+3.5+\"$
\n" ); document.write( " $\"+x+=+23.333+\"$
\n" ); document.write( "You should add 23 and 1/3 liters of 10% ethanol mixture
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+6+%2B+.1%2A23.333+%29+%2F+%28+10+%2B+23.333+%29+=+.25+\"$
\n" ); document.write( " $\"++8.333+%2F+33.333+=+.25+\"$
\n" ); document.write( " $\"+8.333+=+.25%2A33.333+\"$
\n" ); document.write( " $\"+8.333+=+8.333+\"$
\n" ); document.write( "OK \n" ); document.write( "

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