document.write( "Question 891237: I was wondering if you could help me with a problem. I have a problem that is asking me to find the volume of a pentagonal pyramid with base or side measure of 23,and height of 27. Help please?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #539636 by KMST(5328)![]() ![]() You can put this solution on YOUR website! The volume is 1/3 times the area of the base, times the height. \n" ); document.write( "You may have been given a formula to calculate the area of a regular polygon. \n" ); document.write( "A regular pentagon (one whose sides all have the same length and whose angles all have the same measure) can be cut, like a pizza into 5 identical isosceles triangles. \n" ); document.write( "In your pentagon, those triangles would have a base length of 23 and angles measuring 72, 54, and 54 degrees. \n" ); document.write( "The height would be \n" ); document.write( " \n" ); document.write( "So the area of the pentagon is approximately \n" ); document.write( " \n" ); document.write( "Let's round that to 1820. \n" ); document.write( "Then, the volume of a pyramid with a base area of 1820 area units and a height of 27 units , calculated in volume units, would be \n" ); document.write( " |