document.write( "Question 891237: I was wondering if you could help me with a problem. I have a problem that is asking me to find the volume of a pentagonal pyramid with base or side measure of 23,and height of 27. Help please?
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Algebra.Com's Answer #539636 by KMST(5328)\"\" \"About 
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The volume is 1/3 times the area of the base, times the height.
\n" ); document.write( "You may have been given a formula to calculate the area of a regular polygon.
\n" ); document.write( "A regular pentagon (one whose sides all have the same length and whose angles all have the same measure) can be cut, like a pizza into 5 identical isosceles triangles.
\n" ); document.write( "In your pentagon, those triangles would have a base length of 23 and angles measuring 72, 54, and 54 degrees.
\n" ); document.write( "The height would be \"23%2Atan%2854%29\" , and the tangent of \"54%5Eo\" is approximately
\n" ); document.write( "\"tan%2854%5Eo%29=1.3764\" .
\n" ); document.write( "So the area of the pentagon is approximately
\n" ); document.write( "\"23%2A23%2A1.3764%2A5%2F2=1820.289\" .
\n" ); document.write( "Let's round that to 1820.
\n" ); document.write( "Then, the volume of a pyramid with a base area of 1820 area units and a height of 27 units , calculated in volume units, would be
\n" ); document.write( "\"%281%2F3%29%2A1820%2A27=16380\" .
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