document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=891264>Question 891264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ratio of supplementary angle and complementary angle of an angle is 11:5 then what is the measure of that angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #539621 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=539621\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the angle be x\r<BR>\n" );
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document.write( "(180-x)/(90-x) = 11/5\r<BR>\n" );
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document.write( "5(180-x)=11(90-x)\r<BR>\n" );
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document.write( "900-5x=990-11x\r<BR>\n" );
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document.write( "6x=90\r<BR>\n" );
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document.write( "x=90/6<BR>\n" );
document.write( "x=15 deg\r<BR>\n" );
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