document.write( "Question 75139: PLEASE HELP ME!!
\n" ); document.write( "The area of a rectangle of length x is given by 3x^2 + 5x. Find the
\n" ); document.write( "width of the rectangle.
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Algebra.Com's Answer #53961 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Since the area is:
\n" ); document.write( "\"A=L%2Aw\" we can solve for w
\n" ); document.write( "\"w=A%2FL\"
\n" ); document.write( "Now lets plug in our values
\n" ); document.write( "\"w=%283x%5E2%2B5x%29%2Fx\" plug in \"A=3x%5E2%2B5x\" and L=x
\n" ); document.write( "\"w=3x%5E2%2Fx%2B5x%2Fx\"Break up the fraction into two fractions
\n" ); document.write( "\"w=3x%5E%28cross%282%29%29%2Fcross%28x%29%2B5%2Across%28x%2Fx%29\" Divide like terms.
\n" ); document.write( "\"w=3x%2B5\"
\n" ); document.write( "So the width is \"w=3x%2B5\"
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\n" ); document.write( "Check:
\n" ); document.write( "If we multiply L and w we should get A
\n" ); document.write( "\"A=L%2Aw\"
\n" ); document.write( "\"A=x%283x%2B5%29\"Plug in values for w and L
\n" ); document.write( "\"A=3x%5E2%2B5x%29\" So our answer works \n" ); document.write( "

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