document.write( "Question 891156: Again I am unsure where to place this question but any help would be amazing.\r
\n" ); document.write( "\n" ); document.write( "Assume that a normal distribution of data has a mean of 11 and a standard deviation of 2. Use the 68-95-99.7 Rule to find the percentage of values that lie above 9.\r
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Algebra.Com's Answer #539572 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
68 is within 1 standard deviation.
\n" ); document.write( "95 is within 2 standard deviations.
\n" ); document.write( "99 is within 3 standard deviations.\r
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\n" ); document.write( "\n" ); document.write( "i believe that's the rule.\r
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\n" ); document.write( "\n" ); document.write( "you have a mean of 11 and a standard deviation of 2.\r
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\n" ); document.write( "\n" ); document.write( "you want to find the percentage of values that lie above 9.\r
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\n" ); document.write( "\n" ); document.write( "your z score is equal to (x-m/s where x = 9, m = 11, s = 2\r
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\n" ); document.write( "\n" ); document.write( "you get:\r
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\n" ); document.write( "\n" ); document.write( "z = (9 - 11) / 2 = -2/2 = -1.\r
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\n" ); document.write( "\n" ); document.write( "your z score is 1 standard deviation below the mean.\r
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\n" ); document.write( "\n" ); document.write( "this would fall under the 68 rule, except you can't use the rule as is.\r
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\n" ); document.write( "\n" ); document.write( "you have to do some logical analysis.\r
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\n" ); document.write( "\n" ); document.write( "68% of the data is within 1 standard deviation from the mean.\r
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\n" ); document.write( "\n" ); document.write( "this means the z score of the data has a low value of -1 and a high value of +1\r
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\n" ); document.write( "\n" ); document.write( "so 68% of the data is between a z score of -1 and a z score of 1.\r
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\n" ); document.write( "\n" ); document.write( "this means that 32% of the data lies outside this range.\r
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\n" ); document.write( "\n" ); document.write( "this is evenly split between the low side and the high side.\r
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\n" ); document.write( "\n" ); document.write( "this means that 16% of the data lies below a standard deviation of -1 and 16% of the data lies above a standard deviation of 1.\r
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\n" ); document.write( "\n" ); document.write( "your data has a z score of -1\r
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\n" ); document.write( "\n" ); document.write( "this means that 16% of your data lies below a z score of -1 and 68% + 16% = 84% of your data lies above a z score of -1.\r
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\n" ); document.write( "\n" ); document.write( "they want to know the percentage of values that lie above 9.\r
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\n" ); document.write( "\n" ); document.write( "that would be 84%\r
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\n" ); document.write( "\n" ); document.write( "here's a picture of what I mean.\r
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\n" ); document.write( "\n" ); document.write( "the 68-95-99 rule is an approximation.\r
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\n" ); document.write( "\n" ); document.write( "the calculations shown in the picture are more exact.\r
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