document.write( "Question 891173: 12. There are 20 quarts of milk on a supermarket shelf, four of which are spoiled. A customer buys three quarts of milk.
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\n" ); document.write( "(b) How many samples contain exactly two quarts of spoiled milk?
\n" ); document.write( "(c) How many samples contain at least two quarts of spoiled milk?
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Algebra.Com's Answer #539567 by Theo(13342)\"\" \"About 
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There are 20 quarts of milk on a supermarket shelf.
\n" ); document.write( "4 of them are spoiled.
\n" ); document.write( "That means 16 good and 4 bad.\r
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\n" ); document.write( "\n" ); document.write( "A customer buys 3 quarts of milk.\r
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\n" ); document.write( "\n" ); document.write( "Total possible samples that are different from each other is given by the formula of C(20,4) = 20! = 4845\r
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\n" ); document.write( "\n" ); document.write( "Total possible samples that contain exactly 2 quarts of bad milk are equal to C(4,2) * C(16,1) = 6 * 16 = 96\r
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\n" ); document.write( "\n" ); document.write( "Total possible samples that contain exactly 3 quarts of bad milk are equal to C(4,3) = 4\r
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\n" ); document.write( "\n" ); document.write( "Total possible samples that contain at least 2 quarts of bad milk are equal to C(4,2) * C(16,1) + C(4,3) = 96 + 4 = 100\r
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\n" ); document.write( "\n" ); document.write( "C(n,x) = n! / ((n-x)! * x!)\r
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\n" ); document.write( "\n" ); document.write( "For Example:\r
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\n" ); document.write( "\n" ); document.write( "C(4,2) = 4! / (2! * 2!) = 4*3*2*1 / 2*1*2*1 = 6\r
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\n" ); document.write( "\n" ); document.write( "C(16,1) = 16 * 15! / (1! * 15!) = 16 / 1 = 16.\r
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\n" ); document.write( "\n" ); document.write( "C(4,3) = 4! / (1!*3!) = 4*3*2*1 / 1*3*2*1 = 4\r
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