document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=891059>Question 891059</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a triangle is 3cm longer than its width. If the perimeter of the rectangle is 30cm, find its area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #539488 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=539488\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter is a fence around.  P = 2L + 2W<BR>\n" );
document.write( "You're asking first about a triangle and then about a rectangle.  Let's solve for a rectangle, and you can repost if you need a different angle.<BR>\n" );
document.write( "L = W + 3<BR>\n" );
document.write( "Substitute the value of L into the first equation<BR>\n" );
document.write( "P = 2L + 2W<BR>\n" );
document.write( "30 = 2(W+3) + 2W<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "30 = 2W+6 + 2W<BR>\n" );
document.write( "30 = 4W + 6<BR>\n" );
document.write( "Subtract 6 from each side<BR>\n" );
document.write( "24 = 4W<BR>\n" );
document.write( "Divide each side by 4<BR>\n" );
document.write( "6 = W<BR>\n" );
document.write( "If the width is 6, then the length is 9<BR>\n" );
document.write( "Perimeter = 2(9) + 2(6)<BR>\n" );
document.write( "30 = 18 + 12<BR>\n" );
document.write( "30=30<BR>\n" );
document.write( "Success! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );