document.write( "Question 890592: A group of 7 children is going to a movie. In How many ways can the group be seated, if Randy, Sandy, Candy and Dandy refuse to sit next to each other? \n" ); document.write( "

Algebra.Com's Answer #539455 by Edwin McCravy(20055) $\"\"$ $\"About$

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A group of 7 children is going to a movie. In How many ways can the group be seated, if Randy, Sandy, Candy and Dandy refuse to sit next to each other?
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document.write( "Let the seat numbers be:  1,2,3,4,5,6,7\r\n" );
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document.write( "Randy, Sandy, Candy and Dandy must sit in the 4 odd numbered seats.\r\n" );
document.write( "They can be placed in the 4 odd numbered seats in 4! ways.\r\n" );
document.write( "The other three children must be placed in the 3 even-numbered seats.\r\n" );
document.write( "They can be placed in the 3 even numbered seats in 3! ways. \r\n" );
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document.write( "Answer 4!*3! = 24*6 = 144 ways.\r\n" );
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document.write( "Edwin

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