document.write( "Question 891012: An initial deposit of $36,000 grows at an annual rate of 8% for 24 years. Compare the final balances resulting from continuous compounding and annual compounding. (Round your answers to the nearest cent.)\r
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document.write( "from continuous compounding=???
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document.write( "from annual compounding=??? \n" );
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Algebra.Com's Answer #539445 by Theo(13342)![]() ![]() You can put this solution on YOUR website! formula for continuous compounding is f = p * e^(i*n) \n" ); document.write( "i is the interest rate per time period. \n" ); document.write( "n is the number of time periods.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "formula for annual compounding is f = p * (1+i)^n \n" ); document.write( "i is the interest rated per time period. \n" ); document.write( "n is the number of time periods.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "time period is in years. \n" ); document.write( "i = .08 per year. \n" ); document.write( "n = 24 years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your continuous compounding formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = 36,000 * e^(.08*24) which results in f = 245,554.5049\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your annual compounding formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = 36,000 * (1.08)^24 which results in f = 228,282.5065\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you may round the answer to the nearest cent as required.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |