document.write( "Question 891012: An initial deposit of $36,000 grows at an annual rate of 8% for 24 years. Compare the final balances resulting from continuous compounding and annual compounding. (Round your answers to the nearest cent.)\r
\n" ); document.write( "\n" ); document.write( "from continuous compounding=???
\n" ); document.write( "from annual compounding=???
\n" ); document.write( "

Algebra.Com's Answer #539445 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
formula for continuous compounding is f = p * e^(i*n)
\n" ); document.write( "i is the interest rate per time period.
\n" ); document.write( "n is the number of time periods.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "formula for annual compounding is f = p * (1+i)^n
\n" ); document.write( "i is the interest rated per time period.
\n" ); document.write( "n is the number of time periods.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "time period is in years.
\n" ); document.write( "i = .08 per year.
\n" ); document.write( "n = 24 years.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "your continuous compounding formula becomes:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "f = 36,000 * e^(.08*24) which results in f = 245,554.5049\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "your annual compounding formula becomes:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "f = 36,000 * (1.08)^24 which results in f = 228,282.5065\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "you may round the answer to the nearest cent as required.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );