document.write( "Question 890992: Two angles are complementary. The larger of the two is 42° more than twice the smaller. Find the 2 angles. \n" ); document.write( "

Algebra.Com's Answer #539400 by Tatiana_Stebko(1539) $\"\"$ $\"About$

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Let $\"x\"$ be the smaller angle, then the larger angle is $\"2x%2B42%29\"$ . Two angles are complementary, therefore $\"x%2B%282x%2B42%29=90\"$
\n" ); document.write( " $\"x%2B2x%2B42=90\"$
\n" ); document.write( " $\"3x=90-42\"$
\n" ); document.write( " $\"3x=48\"$
\n" ); document.write( " $\"x=48%2F3\"$
\n" ); document.write( " $\"x=16\"$ °-the smaller angle
\n" ); document.write( "the larger angle is $\"2%2A16%2B42=74%29\"$ °
\n" ); document.write( "Check: 16+74=90
\n" ); document.write( "Answer:16° and 74° \n" ); document.write( "

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