document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=890833>Question 890833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains left a station at the same time. one traveled north at a certain speed and the other traveled south at twice that speed. after four hours, the trains were 600 miles apart. how fast was each train traveling? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #539355 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=539355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = 2B<BR>\n" );
document.write( "4(A+b) = 600<BR>\n" );
document.write( "Substitute the value of A from the first equation into the second<BR>\n" );
document.write( "4(2B+B) = 600<BR>\n" );
document.write( "Divide each side by 4<BR>\n" );
document.write( "2B+B = 150<BR>\n" );
document.write( "Add<BR>\n" );
document.write( "3B = 150<BR>\n" );
document.write( "Divide each side by 3<BR>\n" );
document.write( "B = 50<BR>\n" );
document.write( "If the slower train is traveling 50 mph, then the faster train is traveling 100 mph.  Together they travel 150 mph.  Multiply that by four hours to get the total distance of 600 miles.<BR>\n" );
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