document.write( "Question 890866: Susie drove 100 miles to visit a friend. If she had driven 8 miles per hour faster than she did, she would have arrived in 5/6 of the time it actually took. How many minutes did the trip take? \n" ); document.write( "

Algebra.Com's Answer #539337 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+s+\"$ = the speed in mi/hr that would
\n" ); document.write( "get her there non time
\n" ); document.write( "Let $\"+t+\"$ = time in hrs spent driving to
\n" ); document.write( "get her there on time
\n" ); document.write( "---------------------------
\n" ); document.write( "(1) $\"+100+=+s%2At+\"$
\n" ); document.write( "(2) $\"+100+=+%28+s+%2B+8+%29%2A%28%285%2F6%29%2At+%29+\"$
\n" ); document.write( "----------------------------
\n" ); document.write( "(2) $\"+600+=+%28+s+%2B+8+%29%2A5t+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+t+=+100%2Fs+\"$
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) $\"+600+=+%28+s+%2B+8+%29%2A5%2A%28+100%2Fs+%29+\"$
\n" ); document.write( "(2) $\"+600s+=+500%2A%28+s+%2B+8+%29+\"$
\n" ); document.write( "(2) $\"+600s+=+500s+%2B+4000+\"$
\n" ); document.write( "(2) $\"+100s+=+4000+\"$
\n" ); document.write( "(2) $\"+s+=+40+\"$
\n" ); document.write( "-------------------
\n" ); document.write( "(1) $\"+t+=+100%2Fs+\"$
\n" ); document.write( "(1) $\"+t+=+100%2F40+\"$
\n" ); document.write( "(1) $\"+t+=+5%2F2+\"$ hrs
\n" ); document.write( "The trip actually took $\"+60+%2A+%285%2F2%29+=+150+\"$ minutes
\n" ); document.write( "check:
\n" ); document.write( "(2)

\n" ); document.write( "(2) $\"+100+=+25%2A4+\"$
\n" ); document.write( "(2) $\"+100+=+100+\"$
\n" ); document.write( "OK
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