document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=890677>Question 890677</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A Gardener is making a trapezoidal planting, with 32 plants in the front row, 26 in the second row, 20 in the third row and so on. If the pattern is consistent, how many plants will there be altogether if there are two plants in the last row? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #539336 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=539336\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S = ½(a1 + an)n<BR>\n" );
document.write( "S = ½(a1 + an)n<BR>\n" );
document.write( "an = a1 + (n - 1)d<BR>\n" );
document.write( "an = 32 -6(n-1)<BR>\n" );
document.write( "2 = 32 -6n + 6<BR>\n" );
document.write( "6n=36<BR>\n" );
document.write( "n=6<BR>\n" );
document.write( "S = ½(32 + 2)6<BR>\n" );
document.write( "S=1/2*34*6<BR>\n" );
document.write( "S=17*6=102\r<BR>\n" );
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document.write( " </SPAN>\n" );
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