document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=75037>Question 75037</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The operation @ is defined as @(a) = a^2 + 4a -4, for any real number a. Find the value(s) of a for which @(a)= a. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53932 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The operation @ is defined as @(a) = a^2 + 4a -4, for any real number a. Find the value(s) of a for which @(a)= a.<BR>\n" );
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document.write( "If @(a)=a then,<BR>\n" );
document.write( "a^2+4a-4=a<BR>\n" );
document.write( "Subtract \"a\" from both sides to get:<BR>\n" );
document.write( "a^2+3a-4=0<BR>\n" );
document.write( "Factor to get:<BR>\n" );
document.write( "(a+4)(a-1)=0<BR>\n" );
document.write( "Solve for \"a\" to get:<BR>\n" );
document.write( "a=-4 or a=1<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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