document.write( "Question 890812: where a is the altitude above sea level (in miles). If a city has an atmospheric pressure of 11.19 psi, what is its altitude? (Recall that 1 mi = 5,280 ft. Round your answer to the nearest foot.)
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Algebra.Com's Answer #539311 by Theo(13342)![]() ![]() You can put this solution on YOUR website! you need the formula for atmospheric pressure in terms of altitude.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula is normally shown as P = 14.7 * e^(-.21*a).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if your formula is different because they take 14.7 out to more decimal places, then you need to use what you are given instead.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P is the atmospheric pressure. \n" ); document.write( "a is the altitude in miles.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in your problem, P is given as 11.19 and you want to solve for a.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the equation becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "11.19 = 14.7 * e^(-.21*a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of this equation by 14.7 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "11.19 / 14.7 = e^(-.21*a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "take the natural log of both sides of this equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ln(11.19/14.7) = ln(e^(-.21*a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since ln(e^(-.21*a) is equal to -.21*a*ln(e), your equation becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ln(11.19/14.7) = -.21*a*ln(e)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since ln(e) = 1, your equation becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ln(11.19/14.7) = -.21*a\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of this equation by -.21 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ln(11.19/14.7)/-.21 = a\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for a to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a = 1.299176... miles\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since there are 5280 feet in a mile, then you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a = 6859.6495... feet which you can round to 6860 feet.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |