document.write( "Question 890799: The length of a rectangle is 7 yards less than twice its width. If the length was increased by 11 yards and the width decreased by 6 yards, the area would be decreased by 40 square yards. Find the original dimensions of the lot. \r
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Algebra.Com's Answer #539310 by ankor@dixie-net.com(22740)\"\" \"About 
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The length of a rectangle is 7 yards less than twice its width.
\n" ); document.write( " If the length was increased by 11 yards and the width decreased by 6 yards, the area would be decreased by 40 square yards.
\n" ); document.write( " Find the original dimensions of the lot.
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\n" ); document.write( "let w = the original width
\n" ); document.write( "then \"length of a rectangle is 7 yards less than twice its width.\". therefore:
\n" ); document.write( "(2w-7) = the original length
\n" ); document.write( "and
\n" ); document.write( "w(2w-7) = original area
\n" ); document.write( ":
\n" ); document.write( "\"If the length was increased by 11 yards and the width decreased by 6 yards, the area would be decreased by 40 square yards.\"
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\n" ); document.write( "Original area - new area = 40 sq/yds
\n" ); document.write( "w(2w-7) - (2w-7+11)(w-6) = 40
\n" ); document.write( "2w^2 - 7w - (2w+4)(w-6) = 40
\n" ); document.write( "2w^2 - 7w - (2w^2 - 12w + 4w - 24) = 0
\n" ); document.write( "2w^2 - 7w - (2w^2 - 8w - 24) = 0
\n" ); document.write( "Removing the brackets changes the signs
\n" ); document.write( "2w^2 - 7w - 2w^2 + 8w + 24 = 40
\n" ); document.write( "Combine like terms
\n" ); document.write( "2w^2 - 2w^2 - 7w + 8w = 40 - 24
\n" ); document.write( "w = 16 yds is the original width
\n" ); document.write( "then
\n" ); document.write( "2(16) - 7 = 25 yds is the original length
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\n" ); document.write( "See if this checks out
\n" ); document.write( "25*16 = 400 sq yds origiinal area
\n" ); document.write( "36*10 = 360 sq yds new area (added 11 to the length, subtracted 6 from the width
\n" ); document.write( "-------------
\n" ); document.write( "diff: 40 sq yds\r
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