document.write( "Question 890821: find three consecutive odd positive integers such that 2 times the sum of all three is 105 less than the product of the first and second integers \n" ); document.write( "
Algebra.Com's Answer #539308 by ankor@dixie-net.com(22740)\"\" \"About 
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find three consecutive odd positive integers
\n" ); document.write( "x, (x+2), (x+4), their sum: (3x+6)
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\n" ); document.write( "such that 2 times the sum of all three is 105 less than the product of the first and second integers
\n" ); document.write( "2(3x+6) = x(x+2) - 105
\n" ); document.write( "6x + 12 = x^2 + 2x - 105
\n" ); document.write( "Form a quadratic equation on the right
\n" ); document.write( "0 = x^2 + 2x - 6x - 105 - 12
\n" ); document.write( "x^2 - 4x - 117 = 0
\n" ); document.write( "you can use the quadratic formula, but this will factor to:
\n" ); document.write( "(x+9)(x-13) = 0
\n" ); document.write( "The positive solution
\n" ); document.write( "x = 13 is the first odd number, followed by 15 and 17
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\n" ); document.write( "See if this checks out
\n" ); document.write( "2(13+15+17) = 13*15 - 105
\n" ); document.write( "2(45) = 195 - 105\r
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