document.write( "Question 890782: Solve the inequality. State the answer in interval notation. \r
\n" ); document.write( "\n" ); document.write( "4/(x+1) <_ 3/(x+2) \r
\n" ); document.write( "\n" ); document.write( "the symbol in the middle is supposed to mean \"less than or equal to\". So far I've multiplied both sides by (x+1) and (x+2) to try and get rid of the fraction.
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Algebra.Com's Answer #539289 by josgarithmetic(39799)\"\" \"About 
You can put this solution on YOUR website!
Put all the expressions onto one side.\r
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\n" ); document.write( "\n" ); document.write( "Note the critical values of x at -1 and -2.\r
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\n" ); document.write( "\n" ); document.write( "\"4%2F%28x%2B1%29-3%2F%28x%2B2%29=0\", CHECK THE EQUALITY. This may be another critical value.\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by LCD.
\n" ); document.write( "\"4%28x%2B2%29-3%28x%2B1%29=0\"
\n" ); document.write( "\"4x%2B8-3x-3=0\"
\n" ); document.write( "\"x%2B5=0\"
\n" ); document.write( "\"x=-5\", possibly another critical point along with -1 and -2.\r
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\n" ); document.write( "\n" ); document.write( "Look for truth or falseness in the intervals for \"4%2F%28x%2B1%29%3C=3%2F%28x%2B2%29\".
\n" ); document.write( "x<=-5
\n" ); document.write( "\"4%2F%28-6%2B1%29%3C3%2F%28-6%2B2%29\"
\n" ); document.write( "\"-4%2F5%3C-3%2F4\", TRUE.
\n" ); document.write( "\"4%2F%28-5%2B1%29%3C3%2F%28-5%2B2%29\"
\n" ); document.write( "\"-1%3C-1%7D%7D%2C+FALSE.++%7B%7B%7Bx%3C-5\".\r
\n" ); document.write( "\n" ); document.write( "-5<=x<=-2
\n" ); document.write( "\"4%2F%28-3%2B1%29%3C3%2F%28-3%2B2%29\"
\n" ); document.write( "\"-2%3C-3%2F2\", TRUE.
\n" ); document.write( "\"4%2F%28-2%2B1%29%3C3%2F%28-2%2B2%29\", FALSE. \"x%3C%3E-2\".\r
\n" ); document.write( "\n" ); document.write( "-2<=x<=-1, \"x%3C%3E-1\".\r
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\n" ); document.write( "\n" ); document.write( "So far, you know \"x%3C-5\" OR \"-5%3Cx%3C-2\"----- still not finished finding solutions for x.\r
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\n" ); document.write( "\n" ); document.write( "CAN YOU FINISH THESE?\r
\n" ); document.write( "\n" ); document.write( "NEED ALSO TO CHECK\r
\n" ); document.write( "\n" ); document.write( "-2<=x<=-1, \"x%3C%3E-1\".
\n" ); document.write( "-1<=x
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