document.write( "Question 890809: An artifact was found and tested for its carbon-14 content. If 72% of the original carbon-14 was still present, what is its probable age ( to the nearest 100 years)? (Carbon-14 has a half-life of 5,730 years. \n" ); document.write( "
Algebra.Com's Answer #539283 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! An artifact was found and tested for its carbon-14 content. \n" ); document.write( " If 72% of the original carbon-14 was still present, what is its probable age \n" ); document.write( "( to the nearest 100 years)? (Carbon-14 has a half-life of 5,730 years. \n" ); document.write( ": \n" ); document.write( "Using the radioactive decay formula: A = Ao*2^(-t/h), where: \n" ); document.write( "A = Resulting amt after t time \n" ); document.write( "Ao = Initial amt \n" ); document.write( "t = time of decay \n" ); document.write( "h = half-life of substance \n" ); document.write( ": \n" ); document.write( "We will us 1 as the Initial amt, the resulting amt =.72 \n" ); document.write( "1 * 2^(-t/5730) = .72 \n" ); document.write( "Using nat logs \n" ); document.write( " \n" ); document.write( "t = -5730 * \n" ); document.write( "t = 2715.6 ~ 2700 yrs \n" ); document.write( " |