document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=890792>Question 890792</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many consecutive odd numbers do you add to get 625 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #539258 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=539258\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The logical first try would be to halve 625, but 311 and 313 only make 624.<BR>\n" );
document.write( "Let's try thirds. 207 + 209 + 211  = 627<BR>\n" );
document.write( "We know it must have an odd number, so we'll skip 4ths.<BR>\n" );
document.write( "What about 5ths?  625/5=125.  That's our middle number.  121+123+125+127+129= 625<BR>\n" );
document.write( "Success! </SPAN>\n" );
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